I need to know, step-by-step, how to work this problem:

Question

(_6m⁴_n^-2)^-2

( 2m^-4 n   )

Answer 1

expand (6m^4)^-2 x (n^-2)^-2 = (1/36m^8) x n^4

and the denominator becomes

(m^4/2n)

[(1/36) x (m^12) x (n^3)]/2 ---> [(m^12) x (n^3)]/72