business statistics

Question

The null and alternate hypotheses are:

H0 : μd ≤ 0

H1 : μd > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

Day

1 2 3 4

Day shift 10 12 13 18

Afternoon shift 9 10 14 15

At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.

State the decision rule. (Round your answer to 2 decimal places.)

Compute the value of the test statistic. (Round your answer to 3 decimal places.)

What is the p-value?

Between 0.10 and 0.15

Between 0.001 and 0.005

Between 0.005 and 0.01

What is your decision regarding H0?

Do not reject H0

Reject H0

Answer 1

I am not sure they Null and alternative Hypotheses are accuratelyu described. Are you looking to do a chi squared Test that the two samples come from the same distribution? A kolmogorov Smirnov test?

I need more info here