Three adults and four children must pay $100. Two adults and three children pay $70. Find the price of the adults ticket and the price of a child’s ticket

Answer 1

A=Adult price; C=Child price

3A+4C=$100 Multiply by 2.

6A+8C=$200 Use this to subtract below.

.

2A+3C=$70 Multiply by 3.

. 6A+9C=$210 Subtract equation from above.

-(6A+8C=$200)

C=$10 ANSWER 1: One child's fare is $10

.

3A+4C=$100

3A+4($10)=$100

3A+$40=$100

3A=$60

A=$20 ANSWER 2: One adult's fare is $20

.

CHECK:

2A+3C=$70

2($20)+3($10)=$70

$40+$30=$70

$70=$70