Two times the smallest of three consecutive even integers is eight less than twice the largest even integer. Find the integers

Question

Two times the smallest of three consecutive even integers is eight less than twice the largest even integer. Find the integers. Idk where to start

Answer 1

2(x-2) = 2(x+2)-8

2x-4 = 2x +4 -8

-4 =-4, infinitely trios of 3 consecutive even integers will satisfy the requirements.

x-2 is smallest

x = middle integer

x+2 = largest

2S = 2L - 8

plug in any 3 consecutive even integers (or odd integers) and the equation is true

0,2, 4

2(0) = 2(4) - 8

54,56,58

2(54) =2(58) -8

108 = 116 -8

endless solutions, infinitely combinations of 3 even integers

-28,-26, -24

1108,1110,1112

etc.

also odd integers work

1,3,5

2(1) = 2(5)-8

2 =10-8