Find three consecutive even integers such that the sum of the least integer and the middle integer is 32 more than the greatest integer

Question

Please help me! I want to get this math out of way! 

Answer 1

Our 3 integers:

x

y = x+2

z = x+4

 

We also know that:

x + y = 32 + z

 

So let's sub everything for x and solve:

 

x + (x+2) = 32 + (x+4)

2x + 2 = x + 36

x = 34

 

So if x=34 then the other 2 numbers must be 36 and 38.