If f(x)=4x^3-6x^2+3, then f(x)=

Answer 1

When doing derivatives of functions each exponent's value of x will multiply to its coefficient. and then each x values exponent will also decrease by 1.

f(x)=4x^3-6x^2+3x⁰ ......3 can be written as 3x⁰ since they are equivalent.

f '(x)= 3*4x^3-1- 2*6x^2-1+0*3x^0-1 ....simplify

f '(x)= 12x² - 12x ..... Answer

Answer 2

You didn't specify, but I'm assuming you're looking for the derivative of f(x), or f '(x).

Use the power rule for each term:

The derivative of xⁿ is nx^(n-1)

f(x) = 4x³-6x²+3

f '(x) = 3*4x^3-1-2*6x^2-1+0 (The derivative of any constant is 0 because it's slope is 0, so the 3 disappears)

= 12x²-12x

Answer 3

It's unclear what this question is asking as the answer would just be f(x) = 4x³ - 6x² + 3. I'll assume that there is a typo in the question and that it is really asking for f'(x), or the derivative of f with respect to x. In that case, we apply the power rule to each of the components.

f(x) = 4x³ - 6x² + 3

f'(x) = 3(4)x^3-1 - 6(2)x^2-1 + 0

= 12x² - 12x

so f'(x) = 12x² - 12x