Passing by reference in C?

Question

If C does not support passing a variable by reference, why does this work? #include void f(int *j) { (*j)++; } int main() { int i = 20; int *p = &i; f(p); printf("i = %d\\n", i); return 0; }###Output

$ gcc -std=c99 test.c$ a.exei = 21 

Answer 1

Because you are passing a pointer to the integer and then dereferencing it inside the function.