The derivative of ln(2x + 9) is given by d(2x + 9)/dx divided by (2x + 9)
[where 2x + 9 is greater than 0; that is to say, 2x is greater than = -9 or
x is greater than -4.5].
Then write d[ln(2x + 9)]/dx = d(2x + 9)/dx ÷ (2x + 9), which gives
2/(2x + 9).