Anthony I.

asked • 10/13/14

Determine what percentage of the chain is gold, by mass, to at least 1 decimal place?

The water level was 15 milliliters before adding the chain, and 20 milliliters after adding the chain. When I weighed the chain, its mass was 66.3 grams.

I believe the chain is solid metal (not gold plated), but is probably a blend of gold and other metals. I looked up that gold has a density of 19.3 g/ml, while the other metals like silver and copper usually blended with gold have a combined density of about 9.7 g/ml.

Determine what percentage of the chain is gold, by mass, to at least 1 decimal place?
 
----------------------------------------------------------------------------------------------
 
My answers are x=.371 which equals 37.1% which is the gold content
and y=.629 which equals 62.9% which is the other content

When I used 37.1% for the answer it was said it was wrong. Am I messing the equations up?

1 Expert Answer

By:

Alex G. answered • 10/13/14

Tutor
4.9 (13)

Creative Teacher of Math and the LSAT

Christopher R.

Would a change of the depth of the water measured in milliliters be a measure of the volume of the chain in which it occupies? Thsi would indicate the volume of the chain being 5 milliliters. Then to determine its density is to take the ratio of the measured mass to the volume occupied. I attempted to work the problem, and came up with the density of the chain, which is:
 
density=66.3g/5ml=13.26g/ml. This is where I stopped because I need to go back to review chemistry in how to determine the percentage of gold this chain would contain. 
Report

10/13/14

Anthony I.

Alex the water displacement is 5 mL. Starting is 15 mL ending is 20mL, 20-15=5
Report

10/13/14

Alex G.

I definitely misread that as millimeters!  Oops!
Report

10/13/14

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.