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Tae B.

asked • 10/05/14

calculus 3

express dw/dt as a function of t, both by using the chain rule and by expressing w in terms of t and differentiating directly with respect to t. then, evaluate dw/dt at the given value of t.
 
1. w=x/z+y/z: x=cos2t, y=sin2t, z=1/t, t=3
 
2. w=2yex-ln z; x=ln(t^2+1), tan-1t, z=et, t=1

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SURENDRA K. answered • 10/06/14

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