find three consecutive even integers whose sum is equal to eighteen less than four times the largest number.

Question

 intermediate algebra 

Answer 1

Consecutive even integers:
n
n+2
n+4

 

The sum of three consecutive even integers: 

n + (n+2) + (n+4)

is =

equal to eighteen less than four times the largest number

4(n+4) - 18

 

Completed equation:

n + (n+2) + (n+4) = 4(n+4) - 18

 

Just remember to check your final answer and when you do make sure you use the correct values

 

Answer 2

Hi, Amber.

 

Let the numbers be:

 

X, X + 2, X + 4

 

So,

 

X + X + 2 + X + 4 = 4(X + 4) - 18

 

3X + 6 = 4X + 16 - 18

8 = X

X = 8

So,the numbers are: 

 

8, 10, 12