s(t) = 495 + 10t - 4.9t2 where s(t) is the distance traveled at time t
s'(t) = v(t) = velocity at time t is 10 - 9.8t
The ball will hit the ground when s(t) = 0
The quadratic formula will give an extraneous root and t = 11.12
Remember the quadratic formula assumes that the coefficient of the squared term is positive!
Note: I used 9.8 m/sec2 as the acceleration due to gravity.