(8,-10);y= 3/4x+1

Question

Write an equation in slope intercept form of the line that passes through th given point and is parallel to the graph of the given equation

Answer 1

We need a line that is parallel to y=3/4x+1 that goes through (8,-10).  The formula for a line is y=mx+b  Since it is parallel to the given line we already know the slope or m is 3/4, we know the x is 8 and y is -10, we just need to find the y-intercept or b.  We can also use b=y-mx to find the y-intercept. 

b=(-10)-(3/4(8))

b=-10-6

b=-16

The equation is

y=3/4x - 16

Let's plug this back into the y=mx+b formula to make sure

-10=(3/4(8)) - 16

-10=6-16

And that works.