solving for the y-intercept?

solving for the y-intercept?

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From what I'm understanding, you have a quadratic function --- ƒ(x) = (1/2)x^{2} or y = (1/2)x^{2} --- and you are looking to find the y-intercept of this function, which is the point at which the function crosses the y-axis (or, in other words, it is the point at which x=0).

To find the y-intercept, we simply plug in 0 for x in the equation of the function and solve for y. This value for y is the y-intercept. That is,

ƒ(x) = (1/2)x^{2} , x = 0

ƒ(0) = (1/2)(0)^{2}

= (1/2)(0)

= 0

Thus, since ƒ(0)=0, the y-intercept is at the point (0, 0).

Thank You!!!

This was very helpful. I can now explain to the student.

To solve for the y-intercept of an equation, we need to set the x-value equal to 0 and solve for the y value. The resultant y-value is the value where the function crosses the y-axis. By setting x=0, we get y=(1/2)*(0)^2 = 0. The y-intercept of y=(1/2)x^2 is 0.

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I am not sure what you question is. Could your write out the whole problem?