If a baseball is projected upward from ground level with an initial velocity of 96 feet per second, then it’s height is a function of time.

Question

Given by s= -16t^2 + 96t. 

what is the maximum height reached by the ball? 

Answer 1

 

 -16t^2 + 96t = 0

 

 16t^2 - 96t = 0

 

 A=16 B=-96 C=0

 

 -b/2a =  96/(2 * 16) = 96/32 = 3

 

Max height at t=3 seconds

 

-16*3^2 + 96*3 =

 -16*9 + 96*3 =

 -144 + 288 = 144