Kenneth S. answered • 05/10/18
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P(Jack, then another Jack, w/o replacement) = (1/13)(3/51) which you may simplify
Kenneth S.
1/13 = 4/52, the probability of a Jack, on the first draw.
therefore, of the 51 remaining cards, there are three jacks remaining for the second draw.
YOU TYPED 3/51 WRONG, BTW!
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05/10/18
Jake M.
05/10/18