Joshua C.

asked • 04/06/18# This sequence firm term is equal to four, and the value of each term after the first term is two times greater than the previous term.

This is an a word problem but I cannot find the pattern of the problem. I'm also having trouble finding the pattern and who much it's increasing.

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## 2 Answers By Expert Tutors

Andrew M. answered • 04/07/18

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Each term is 2 times the previous term:

Depending on what you are trying to determine, the pattern is...

Given a term the next is twice as much

**a**

_{n}= 2a_{n-1}Any term in the geometric sequence can be found by multiplying the first

term by the common ratio a total of (n-1) times

term by the common ratio a total of (n-1) times

**a**

_{n}= a_{1}(r)^{n-1 }where r is the common ratio..., in this case r=2, a

_{1}=4

**a**

_{n}=4(2^{n-1})Example: Find a

_{10}a

_{10}= 4(2^{9}) = 20484, 8, 16, 32, 64, 128, 256, 512, 1024,

**2048**Pattern is verified since the 10th term is 2048

Mark M. answered • 04/06/18

Tutor

5.0
(243)
Mathematics Teacher - NCLB Highly Qualified

4, 8, 16, 32, 64, 128, ...

Joshua C.

Thanks

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04/06/18

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Mark M.

04/06/18