in a trapezium ABCD, angle ABD= 35 degrees, angle BAD = 110 degrees and AB is parallel to DC. calculate; angle ABD and angle BDC. (plz also give me the sketch)

Question

geometry of o levels

Answer 1

draw a trapezoid with the top parallel to the bottom. Label the angle in the bottom left corner (A) and continue counter-clockwise with B, C, and D. Draw a line from B to D.

 

Angle BAD (which is angle A) is 110 degrees.

 

Angle ABD is 35 degrees..

 

The third angle in this triangle which is ADB must be 35 degrees because the three angles of a triangle sum to 180 degrees.

 

Angle BDC is also 35 degrees because it is opposite interior angle with angle ABD given AB and DC are parallel and line segment DB is the transversal.