Find dy/dx where xe^y = 6y^3 - 8xy^2

Question

I just dont know how to do it

Answer 1

xe^y = 6y³ - 8xy²

 

e^y + xe^y(dy/dx) = 18y²(dy/dx) - 8y² - 16xy(dy/dx)

 

dy/dx(xe^y - 18y² +16xy) = -e^y - 8y²

 

dy/dx = (-e^y - 8y²) / (xe^y - 18y² + 16xy)