
Andy C. answered 02/02/18
Tutor
4.9
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Math/Physics Tutor
f(x) = ln(x) ----> f(1) = ln(1) = 0
f'(x) = 1/x = x^(-1) ---> f'(1) = 1
f''(x) = -x^(-2) = -1/x^2 ---> f''(1) = -1
f'''(x) = 2x^(-3) ---> f'''(1) = 2
f4(x) = -6x^(-4) ---> f4(1) = -6
f5(x) = 24x^(-5)
P(x) = f(1)/0! *x^0 + f'(1)/1!*x + f''(1)/2!*x^2 + f'''(1)/3!*x^3 + f4(1)*x^4/4!
= x - (1/2)x^2 + (1/3)x^3 + (1/4)x^4 + ... + (1/n)x^n