w^2+14w+34 = 13

Question

its an albebra problem from homework quadratic formula

Answer 1

The quadratic formula is (-b ± √(b^{2 -} 4(a)(c)) / (2a))

 

 

The goal would be to recognize which numbers represent  a, b, and c and then plug them into the quadratic formula.

Original equation. w^2 + 14w + 34 = 13

Step 1. Subtract 13 from both sides. w^2 + 14w + 21

Step 2. a = 1    b = 14   c = 21            (a=1 think of it as an invisible number in front of w^2)

Step 3. plug into quadratic formula.                -14 ± √14² - 4 (1)(21)  /   2 (1)

Step 4. simplify -14 ±  (√196 - 84)  / 2 

Step 5. Solve (-14 ± 10.58) / 2

 

Does that help?