Eric Y. answered • 03/24/14

SAT Prep

_{n}= A

_{1}* (k)

^{n}k is the common ratio, and A

_{1}is the first term

_{n}you can find A

_{11}by replacing n with 11. Use your calculator.

Eric Y. answered • 03/24/14

Tutor

5
(5)
SAT Prep

Geometric sequence is a sequence where a term is found by multiplying the previous term by a number (common ratio).

A_{n} = A_{1} * (k)^{n} k is the common ratio, and A_{1} is the first term

You have to find the common ratio, and then you can write the equation.

If you are confused about how to find the common ratio, try do the previous problem first.

After you write the equation for A_{n} you can find A_{11} by replacing n with 11. Use your calculator.

Janis M. answered • 03/24/14

Tutor

4.9
(168)
Make math your 2nd language. Use it or lose it.

An= (14*10^n-1)/(11^n-1) so that A11=(14* 10^10)/(11^10)

Kyle M. answered • 03/24/14

Tutor

4.9
(229)
Certified Educator with Masters, Tutoring 3rd Grade Through College

Here's a little clue to help you get on track:

This sequence is 14(10^0/11^0), 14(10^1/11^1), 14(10^2/11^2), 14(10^3/11^3),...

So, the terms are:

1. 14(1/1) or 14

2. 14(10/11) or 140/11

3. 14(100/121) or 1400/121

4. 14(1000/1331) or 14000/1331

etc.

Express the exponents as terms in the sequence:

The 1st term gets an exponent of zero;

The 2nd term gets an exponent of one;

The 3rd term gets an exponent of two;

etc.

So each term gets an exponent of n-1. Good luck!

A(n)=14(10/11)^n for n=0,1,2,3,4,...

n=0, A(0)=14

n=1, A(1)=140/11

n=2, A(2)=14(100/121)=1400/121

n=3, A(3)=14(1000/1331)=14,000/1331

.

.

n=11, A(11)=14(10/11)^11=14(10^11)/(11^11)=14(100,000,000,000)/285,311,670,611=

1,400,000,000,000/285,311,670,611

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.