If the detector is capturing 3.2*10^8 photons per sec at this wavelength, what is the total energy of the photons detected in 1 hour?

Question

A stellar object is emitting radiation at 3.60 mm. 

Answer 1

E = hf

f = c/lambda = 3x10^8 ms^-1/3.6x10^-3 m  

f = 8.33x01^10 s^-1

E = 6.626x10^-34 Jsec x 8.33x10^10 sec^-1= 5.5x10^-23 J/photon

 

3.2x10^8 photons/sec x 5.5x10^-23 J/photon x 60 sec/min x 60 min/hour = 6.3x10^-11 J/hour