J.R. S. answered 03/25/17
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1 mole of any gas at STP will occupy 22.4 liters. The volume of the aerosol spray can is not relevant if the question asks for the volume occupied by 2.30 g propane gas.
2.30 g C3H8 x 1 mole C3H8/44.1 g = 0.0227 moles C3H8
0.0227 moles C3H8 x 22.4 L/mole = 0.508 liters of C3H8 (to 3 significant figures)