
Mohammed R. answered 01/02/17
Tutor
New to Wyzant
Specialist in GED and College Prep Math
Let,
Length of rectangle = l
Width of rectangle = w
Total length of fence = x
So, l*w = 384
w = 384/l..........(1)
As the area must be divided by a fence parallel to the 2 shortest sides, let the shortest side be w and the longest be l
x = 3l + 2w
= 3l + 768/l [Plug in w from (1)]
Take the derivative,
x' = 3-768/l2
Taking x' = 0,
3-768/l2 = 0
3 = 768/l2
3*l2 = 768
l2 = 256
3*l2 = 768
l2 = 256
l = 16
Plug l into equation (1) and solve for w,
w = 384/16
= 24
Hence, an outer rectangle of 16m*24m will minimize the amount of fence used