
Kenneth S. answered 11/10/16
Tutor
4.8
(62)
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
I asume that your problem is equivalent to the product of the permutation values
8P3 and 4P2, which is 336 times 12 = 4032.

Kenneth S.
Thanks. Do you have a decent scientific (or graphing) calculator?
I formerly used TI-83/84 before retiring, and now just use casio fx-350 ES Plus; each of these will have an nPr and an nCr function.
On the casio, to do 7P4 I would press 7, then press gold (shift) X keys [this puts letter P on screen), then press 4 and = keys.
Of course, there's always the manual way to do it. 7P4 = 7! / (7-4)! and in this, the tail end factors [3!] all cancel out so the value of 7P4 is 7 times 6 times 5 times 4, or 840.
On theTI calculator, you need to get into the MATH submenu "PRB" for probability, and scroll down to the nPr option, after first entering 7 and subsequently entering 4; just before you press Enter to get the calculation done, the screen would look like this: 7 nPr 4
Report
11/10/16
Mary S.
P(7, 4) · P(6, 3)
P(5, 4)
11/10/16