Mark M. answered 10/23/16
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Yes. For example, let f(x) = x2. Let a = -2, b = 1. Then f(x) is continuous on [-2,1] and is differentiable on (-2,1). f(-2)≠f(1), c = 0 is in the interval (-2,1) and f(c)=0.
Nathan K.
10/23/16