Rolle's theorem cannot be applied because the function is not continuous at 0. The limit as x tends to 0 of 1 - x is 1, while f(0) = 0.
Nathan K.
asked 10/23/16Rolle's Theorem and Piece Wise Functions
The piece wise function f(x)= 0 , x=0 is differentiable on (0,1) and satisfies f(0)=f(1), but its derivative is never
1-x , 0<x≤1
zero on (0,1). Can Rolle's theorem apply to the function, or is it contradicted?
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