
Norbert W. answered 07/29/16
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1) Given the equation is 20y = x2
This is a parabola with the vertex at (0, 0)
Assuming the bulb is placed at the focus of the parabola and the distance between the vertex and the focus is p, then 4p = 20 and p = 5. The bulb would be 5 units from the vertex.
2) If a is the length of the semi-major axis and b is the length of the semi-minor axis, then the eccentricity of the ellipse is e = √(1 - (b/a)2)
The length of the major axis is 36.2 A.U., the length of the semi-major axis is a = 18.1 A.U.
The length of the minor axis is 9.12 A.U., the length of the semi-minor axis is b = 4.56 A.U.
Putting these values into the equation for eccentricity, e = 0.968