Don L. answered 05/10/16
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Abi, solving inequalities is not much different than solving equalities.
3 - 4 * (3x - 4) ≥ 3 * (2 - 3x)
Clear parenthesis:
3 - 12x + 16 ≥ 6 - 9x
Get the numbers on one side and the variables on the other side:
Subtract 6 from both sides:
13 - 12x ≥ -9x
Add 12x to both sides:
13 ≥ 3x
Divide both sides by 3:
13/3 ≥ x
Answer: x ≤ 13/3
Check:
Substitute for x:
Let x = 13/3.
3 - 4 * (3 * 13/3 - 4) ≥ 3 * (2 - 3 * 13/3)
3 - 4 * (13 - 4) ≥ 3 * (2 - 13)
3 - 4 * 9 ≥ 3 * -11
3 - 36 ≥ -33
-33 ≥ -33, checks.
Now check for x = 14/3
3 - 4 * (3 * 14/3 - 4) ≥ 3 * (2 - 3 * 14/3)
3 - 4 * (14 - 4) ≥ 3 * (2 - 14)
3 - 4 * 10 ≥ 3 * -12
3 - 40 ≥ -36
-37 ≥ - 36, which is false.
Now check x = 12/3, or x = 4.
3 - 4 * (3 * 4 - 4) ≥ 3 * (2 - 3 * 4)
3 - 4 * (12 - 4) ≥ 3 * (2 - 12)
3 - 4 * 8 ≥ 3 * -10
3 - 32 ≥ -30
-29 ≥ - 30, which is true.
3 - 4 * (12 - 4) ≥ 3 * (2 - 12)
3 - 4 * 8 ≥ 3 * -10
3 - 32 ≥ -30
-29 ≥ - 30, which is true.
Questions?

Don L.
tutor
Glad to be of help. One thing that makes the inequalities different from equalities, if you have:
-3x < 6
When you divide by -3, you must reverse the inequality sign.
x > -2
OK?
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05/10/16
Abi P.
05/10/16