Don L. answered 05/01/16
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Daniellia, the best way to solve a problem like this is with a table.
Let x be the rate, miles per hour of the first car. The x - 5 will be the rate, miles per hour of the second car.
In this problem, time will be the same for both cars.
To solve use the D(istance) = R(ate) * T(ime) equation.
Car Distance Rate Time
----------------------------------------
1 490 x
2 455 x - 5
Car 1:
D = R * T
Substitute for D and R, solve for T:
490 = x * T
T = 490 / x
Car 2:
D = R * T
Substitute for D and R, solve for T:
T = 455 / (x - 5)
Since the time is the same for both cars, we can equate the two time equations:
490 / x = 455 / (x - 5)
Cross multiply:
490 * (x - 5) = 455 * x
Clear parenthesis:
490x - 2450 = 455x
Subtract 455x from both sides:
35x - 2450 = 0
Add 2450 to both sides:
35x = 2450
Divide both sides by 35:
x = 70
Car 1 traveled at 70 miles per hour.
Car 2 traveled at 70 - 5, or 65 miles per hour.
Questions?