Find an equation of the line that (a) has the same y-intercept as the line y+4x-11=0 and (b) is parallel to the line -12x-7y=3.

Question

Find an equation of the line that (a) has the same y-intercept as the line y+4x−11=0 and (b) is parallel to the line −12x−7y=3.

Write your answer in the form y=mx+b.

Answer 1

One has to get the equations in the form: y = mx + b

 

where m is the slope.

 

and b is the y-intercept

 

The first equation: y + 4x -11=0

 

add 11 to both sides

 

y+4x=11

 

now subtract 4x from both sides

 

y = -4x +11

 

we want the y-intercept from this equation. and that's 11

 

Now for the second equation. -12x-7y=3

 

first add 12x to both sides

 

we get -7y = 12x +3

 

now divide both sides by -7

 

we get y = -(12/7)x - 3/7

 

we want the slope from this equation. that is -12/7

 

the answer we want is y = -(12/7)x + 11