The length of a rectangle is 4 less than its width. If the area is 117 sq. meters, find its dimensions.

Question

 The length of a rectangle is 4 less than its width. If the area is 117 sq. meters, find its dimensions.

 

dont know how to do this need help

 

Answer 1

This is pretty straight forward.

First the area of a rectangle is given by the product of the length and the width and in this case the area is known.

Second the length is an unkown and since we are doing algebra lets call it x

Finally the width is 4 less than the width which is (x-4) units....x will be in meters and the width is 4 meters less then the length.

 

Putting it together we have x(x-4) = 117 m^2

then

x^2 - 4x = 117

 

one could use the solution for the quadratic or one could plug in a few numbers as test for the length

10 by 10 is 100 square meters

10 by 14 is 140 square meters

13 by 9 is 117 square meters....x is 13 and x-4 is 9

 

I used approximation once I had determined the relationship between the area of the rectangle and the perimeter of the rectangle