-3x-10=40+3x

Question

whats the answer

 

Answer 1

-3x – 10 = 40 + 3x

+3x               + 3x     Add 3x to both sides.

_____________

-10 = 40 + 6x

-40    -40                 Subtract 40 from both sides

___________

-50 = 6x

---- -----          Divide by 6 on both sides

6       6

-50/6 = x

Reduce the fraction by dividing 2 in both numerator and denominator and you get: -25/3

Mixed fraction: -8 1/3

Answer 2

     -3x - 10 = 40 + 3x

Since you have one unknown variable (x), your goal is to try and solve for this variable. To do so, you need to isolate this variable to one side of the equation. That is, you need to isolate the variable x by moving all terms that contain x to one side of the equation and moving all other terms to the other side of the equation.

First, subtract 3x from both sides of the equation:

     -3x - 10 = 40 + 3x

     -3x                - 3x

 ____________________

     -6x - 10 = 40 + 0       ==>      -6x - 10 = 40

Next, add 10 to both sides of the equation:  

     -6x - 10 = 40

         + 10    + 10

 _________________

     -6x + 0 = 50         ==>       -6x = 50

Then, divide both sides of the equation by -6 to solve for x:

     -6x = 50

    (-6x) / -6 = (50) / -6

      x = -50/6

Since both -50 and 6 are multiples of 2, -50/6 can be reduced to -25/3. 

Thus,     x = -25/3       

Answer 3

-3x-10=40+3x Add 3x to both sides -10 = 40 + 6x Subtract 40 from both sides -50 = 6x Divide both sides by 6 x = -50/6 x = 8 2/6 = 8 1/3