Youngkwon C. answered • 12/05/15

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Hi Shelby,

From a

_{n+1}= ka_{n}, we get a

_{n+1}/a_{n}= kwhich means the ratio of two consecutive terms is k.

So, the general equation for the sequence is

a

_{n}= k^{n-1}a_{1} = 6k

^{n-1} a

_{1}= 6 a

_{2}= 6k a

_{3}= 6k^{2} a

_{4}= 6k^{3} a

_{5}= 6k^{4} ...