
Kathy G. answered 11/01/15
Tutor
5.0
(129)
HOMEWORK HELP when you need it.
Hey Melanie
I'm Kathy :-)
I assume you want a line that goes through the given point and parallel to the given line.
A line that is parallel to y=2/3 x + 5 will have the same slope.
slope of that line is 2/3...the number in front of the x.
So our new line will have slope of 2/3.
now we need the y-intercept.
To find that start with a slope intercept equation
y=mx+b
plug in the slope that we already know...it goes in for x...will be the number in front of x
y= 2/3 x + b.
now all we need is a number to plug in for the "b" and we will have it.
to get the "b"...start with the part you already know.
y = 2/3 x + b
use the point they gave you...(-3,1)...and get x and y from it
x will be -3 and y will be 1
plug that in
1= 2/3 ( -3) + b
now we solve for b
1 = -2 + b
3 = b
now we have the b we need
y = 2/3 x + b
y = 2/3 x + 3
and you are done
If you have questions about any of that and need me to explain it better just let me know.