Aubree T.

asked • 10/24/15

Linear Systems Theory HW

I have this as homework in an integrated three math class. We are working on linear systems (thanks for the help in advance!!!):
Bob purchases the same four items every week (apples, ice cream, cans of soup, and peanut butter), but he refuses to tell us how much each of them costs. (Maybe he’s embarrassed). He will, for some reason, tell us how many of each thing he bought, and the total bill for that week.
 
a. Assuming he buys each item each week, how many weeks would it take you to figure out how much each item costs? Why would it take that long to figure out?

b. Would any additional weeks of data make it easier or harder to figure out how much each item costs?

c. Would it help if he didn’t purchase some of the items some week? Would that allow you to figure out how much each thing cost in fewer weeks?

d. Could Bob make his purchases in such a way that you couldn’t ever figure out how much each item was? How might he do this?



2 Answers By Expert Tutors

By:

Michael J. answered • 10/24/15

Tutor
5 (5)

Applying SImple Math to Everyday Life Activities

Hilton T.

tutor
Michael,

Correction to your reasoning.

You can solve a system of 4 equations with 4 unknowns if the equations are linearly independent.
The second, third and fourth equations are essentially the same (they are linearly dependent).
You cannot solve two equations with four variables.
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10/25/15

Aubree T.

What equations would be correct?
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10/24/15

Michael J.

Hilton,
 
It will help the student if you show your equations to support your answers. 
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10/25/15

Hilton T.

tutor
It is now up to the student to fill in the gaps in all I have said. I do not want to provide a complete solution. My answer is merely supposed to be a guide to the student. 
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10/25/15

Aubree T.

Are Michael's equations correct, though? I'm not exactly sure how to start them..
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10/25/15

Hilton T.

tutor

Michael uses a,b,c, and d to represent the number of items bought each week. I would go further and state a1,b1,c1,d1. First week a2,b2,c2,d2. Second week. a3,b3,c3,d3. Third week. etc. Where the a, b, c, and d's may be different for each week. You need four different independent equations to solve the four unknowns. If say, week1, a=1, b=1,c=1,d=1, and in week 2, a=2,b=2,c=2,d=2, the equations for the two weeks are essentially the same. So even if for the next two weeks, the a, b, c, and d are all different, and we have two different equations, then for the four weeks, there are only three idependent equations which are not sufficient to determine the four unknowns. You will need at least 1 more week of data to determine. I hope I have shed some clarity on this topic. Etc.

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10/25/15

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