
Vidya R. answered 09/01/15
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Assuming the ball was simply dropped (initial velocity of 0) then the distance travelled will simply be
(1/2)*g*t^2 where g = acceleration due to gravity.
since we are dealing with feet, we will consider g to be ~32.2 ft/s^2 (source:https://en.wikipedia.org/wiki/Standard_gravity)
plugging the values in gives
81 = 1/2*32.2 * t^2
=> t^2 = 81/16.1 = 5.03
=> t ~2.24s