HOW DO I MULTIPLY BINOMIALS USING THE FOIL METHOD? (y^2Z^2 - 8)(Y^2Z^2 + 5)

Question

I DO NOT UNDERSTGAND THIS PLEASE HELP

Answer 1

You can multiply the given binomials using the FOIL method. FOIL means First, Outside, Inside, Last. Let's show that with your given problem:

(y²z² - 8)(y²z² + 5)

Your "First" terms are y²z² and y²z² which multiply like this:

y²z² * y²z² = y²⁺²z²⁺² = y⁴z⁴

Next you multiple the "Outside" terms, y²z² and 5, like this:

y²z² * 5 = 5y²z²

Third you multiple the "Inside" terms, -8 and y²z², like this:

-8 * y²z² = -8y²z²

Finally you multiple the "Last" terms, -8 and 5, like this:

-8 * 5 = -40

The last step is to put it all together. Here is the whole process:

(y²z² - 8)(y²z² + 5)

y^₄z⁴ + 5y²z² - 8y²z² - 40

y⁴z⁴ - 3y²z² - 40

That's all there is to it!

 

 

Answer 2

(y²z² - 8)(y²z² + 5)

(y²z²)² - 8y²z² + 5y²z² - (5*8)

y⁴z⁴ - 3y²z² - 40