
Andrew D. answered 06/24/15
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Nicole,
1. y1=22x-132; y2=16x+600
2. y1(20)=22(20)-132=$308; y2=16(20)+600=$920
3. I must leave that to you.
4. m1=$22/hour>m2=$16/hour. The rate of hourly pay is the same as the slope of the line. Job 1's slope is greater.
5. The initial values occur with no work done y1(0)=-132; y2(0)=600 Job 2 has a bonus rather than a charge so its initial value is grater.
6. y1(60)=1320-132=1188 y2(60)=960+600=1460. I would prefer job 2 on working 60 hours since my income is greater.
y1(200)=4400-132=4268 y2(200)=3200+600=3800. If I were to work200 hours, I would prefer job 1 since 4268>3800