can someone shows me how to do this problem?

Question

There were 420 people who attended a play
.
The admission price
was $3 for adults and
$1 for children. The admission receipts totaled $960. How many adults and how many
children attended
the play
?
2x2 System

Answer 1

I didn't use algebra to answer it, but basically this was the process.

1st  I divided $960 by 3 and got how many adults this would be which was 320 adults.

2nd  I worked my way to 420 people by subtracting adults and replacing them with children. For every adult, there was 3 children that attended.

3rd  My first estimate was 280 adults and 120 children, but this was only 400 total people, so I knew I was close, but not quite there.

4th  I then took 10 adults away and replaced them with 30 children. This worked: 270 adults + 150 children = 420 people. The adults paid a total of $810 + $150 (children) = $960.00

 

I guess this was the long way around, but it worked for me.

Answer 2

you can use two variables and two equations or just one variable and one equation

x=# of $3 tickets

420-x=# of $1 tickets

$3(x)+$1(420-x)=$960

3x+420-x=960

2x+420=960

2x=960-420

2x=540

x=540/2

x=270 $3 tickets

420-270=150 $1 tickets