Philip P. answered • 04/19/15

Tutor

5.0
(472)
Effective and Patient Math Tutor

s(t) = t

^{2}+ t**a)**s(1) = 1

^{2}+1 = 2, s(3) = 3

^{2}+3 = 12. So the end points of the interval are (1,2) and (3,12). The average velocity in this interval is the slope of the secant line connecting the two points:

**average velocity = (12-2)/(3-1) = 5 ft/sec**

**b)**The instantaneous velocity is the derivative of s wrt t:

instantaneous velocity = ds/dt = d(t

^{2}+t)/dt = 2t+1At t = 1:

**instantaneous velocity = 2*1 + 1= 3 ft/sec**

Philip P.

Right you are. Thanks for the comment. I've corrected my answer.

Report

04/19/15

Michael J.

[t^{2}+ t]= 2t + 104/19/15