Search
Ask a question
0 0

write the equation of the line in standard form, that passes through the given point and is parallel to the given: P95,-20; 3y+1=-4x

what i did:

3y+1=-4x

slope=-4/3

(y+2=-4/3x-20)3

3y+6=-4x-20

4x+3y=-26         

Comments

What are coordinates of the given point? P95, -20 or P(5,-2)?

Tutors, please sign in to answer this question.

1 Answer

You did almost everything correctly. You found the right slope and plugged it back into the equation which should look like y-(-2)=-4/3(x-5) There should be parenthesis around the (x-5). When you continue solving, you will get a positive 20 (the -4/3 and the -5 cancel out) so you will end up with 14 on the right side of the equation. If you plug your given point (5,-2) back in, it will check out :)

Comments

Are you using the point (5,-2)?  I think that was the original problem but I'm not sure.  Parallel to 3y+1=-4x