what i did:

3y+1=-4x

slope=-4/3

(y+2=-4/3x-20)3

3y+6=-4x-20

4x+3y=-26

what i did:

3y+1=-4x

slope=-4/3

(y+2=-4/3x-20)3

3y+6=-4x-20

4x+3y=-26

Tutors, please sign in to answer this question.

You did almost everything correctly. You found the right slope and plugged it back into the equation which should look like y-(-2)=-4/3(x-5) There should be parenthesis around the (x-5). When you continue solving, you will get a positive 20 (the -4/3 and the -5 cancel out) so you will end up with 14 on the right side of the equation. If you plug your given point (5,-2) back in, it will check out :)

Deirdre W.

Enthusiastic Orton-Gillingham trained Teacher/Reading/Writing

Teaneck, NJ

4.6
(146 ratings)

Steven L.

Cornell Alum - Enthusiast in Math and Science (Regents, SAT, AP exams)

Fresh Meadows, NY

4.9
(108 ratings)

Sarah E.

English and Biology Tutor; Professional Zoo Writer

New York, NY

4.7
(10 ratings)

## Comments

What are coordinates of the given point? P95, -20 or P(5,-2)?