using the definition and find f'(2), where f(x) = 1/√x-1

Answer 1

f(x) = 1/sqr(x-1) = (x-1)^.5

f'(x) = .5/sqr(x-1) = 1/2sqr(x-1)

f'(2) = 1/2sqr(2-1) = 1/2