∠A and \angle B∠B are complementary angles. If m\angle A=(2x+30)^{\circ}∠A=(2x+30) ∘ and m\angle B=(6x-12)^{\circ}∠B=(6x−12) ∘ , then find the measure of \angle A∠A.

Answer 1

∠A and \angle B∠B are complementary angles

for that ∠A + ∠B=90

∠A =2x+3

∠B=6x-12,

so we can do, (2x+3)+(6x-12)=90

2x+3+6x-12=90

8x-9=90

8x=90+9

8x=99

x=99/8=12.375

Now x=12.375

∠A =2x+3=2(12.375)+3=27.75