First write the integration as [1/(t − 1)]∫(y + t)dy.
[1/(t − 1)]∫(y + t)dy then goes to [1/(t − 1)] times {0.5y2 + ty}.
State the final answer as a stacked ratio or fraction:
{0.5y2 + ty}
---------------- + C.
(t − 1)
Nihal M.
asked 09/01/21Can anyone integrate this equation with respect to y and explain how. Thank you
First write the integration as [1/(t − 1)]∫(y + t)dy.
[1/(t − 1)]∫(y + t)dy then goes to [1/(t − 1)] times {0.5y2 + ty}.
State the final answer as a stacked ratio or fraction:
{0.5y2 + ty}
---------------- + C.
(t − 1)
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