∫3xex dx
3x = eln3^x = exln3 [Identity: ln(ab) = b*ln(a)]
∫exln3ex dx = ∫e(1+ln3)x dx
Can you finish it from here? Remember, (1+ln3) is just a constant. Let u = (1+ln3)x, du = (1+ln3)dx.
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