A rectangular room of length 6 meters has six 18 W LED lights

Question

What is the maximum width of the room if the lamp power density requirement of 5 W/m^2 is to be met?

Answer 1

Given:

Length: 6 Meters

Width: TBD

# Lights: 6

Watts / Light: 18

Total Watts Available: 6 x 18 = 108

Watts Rq’d / Square Meter: 5

Solve for Width:

Watts rq’d / Sq M = total watts Avail / (Length x Width); Substitute In for known values:

    5 = 108 / (6 x Width)

               Width = 108 / (5 x 6)

             Answer:  Width = 3.6 Meters

Check: Total Watts Avail / (L x Width) = Watts / M Sq’d

  108 / (6 x 3.6) = 5 Watts / M Sq’d