leap year methods

Question

A common year in the modern Gregorian calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 is a leap year.

Ex: If the input is:

1913

the output is:

1913 is not a leap year.

Your program must define and call the following method. The method should return true if the input year is a leap year and false otherwise.

public static boolean isLeapYear(int userYear)

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

}

}

Answer 1

import java.io.*;

class LabProgram

{

private Console console;

LabProgram()

{

console = System.console();

}

public int PromptForInt( String msgStr)

{

System.out.println("******************************");

System.out.print(msgStr);

String inbuff = console.readLine();

return(Integer.parseInt(inbuff));

}

public boolean isLeapYear(int userYear)

{

boolean boolReturn=true;

if ((userYear%4)==0) // MUST be divisible by 4

{

if ((userYear%100)==0) //IF it is a century, it must be divisible by 400

{

boolReturn = ((userYear%400)==0);

}

}

else //not divisible by 4

{

boolReturn=false;

}

return(boolReturn);

}

public void Go()

{

int year = PromptForInt("Please input the year :>");

if (isLeapYear(year))

{

System.out.println( year + " is a leap year" );

}

else

{

System.out.println( year + " is not a leap year");

}

}

public static void main(String args[])

{

LabProgram x = new LabProgram();

x.Go();

}

}