Count characters - methods

Question

Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in the string.

Ex: If the input is:

n Monday

the output is:

1

Ex: If the input is:

z Today is Monday

the output is:

0

Ex: If the input is:

n It's a sunny day

the output is:

2

Case matters. n is different than N.

Ex: If the input is:

n Nobody

the output is:

0

import java.util.Scanner;

public class LabProgram {

/* Define your method here */

public static void main(String[] args) {

/* Type your code here. */

}

}

Answer 1

import java.io.*;

class LabProgram

{

private String str;

private char chTargetChar;

public String GetStr() { return(str); }

public char GetTargetChar() { return(chTargetChar); }

public void SetStr( String s) { str = new String(s); }

public void SetTargetChar( char ch) { chTargetChar = ch; }

public LabProgram()

{

str=null;

chTargetChar = '?';

}

public void Input()

{

Console console = System.console();

String inbuff = null;

System.out.print(" Please input the String :>");

inbuff = console.readLine();

str = new String(inbuff);

System.out.print(" Please input the character :>");

inbuff = console.readLine();

chTargetChar = inbuff.charAt(0);

}

// returns the # of instances of chTargetChar in String str

public int CountChars()

{

int iCountReturn=0;

if (str!=null)

{

int N = str.length();

for (int iLoop=0; iLoop<N; iLoop++)

{

if (chTargetChar == str.charAt(iLoop))

{

iCountReturn++;

}

}

}

return(iCountReturn);

}

public static void main(String args[])

{

LabProgram x = new LabProgram();

x.Input();

String str = x.GetStr();

char chTarget = x.GetTargetChar();

System.out.println(" There are " + x.CountChars() + " appearances of " + chTarget + " in string " + str);

x.SetStr("The quick brown fox jumped over the lazy dogs");

for (char chLoop='a'; chLoop<='z'; chLoop++)

{

x.SetTargetChar(chLoop);

System.out.println(" There are " + x.CountChars() + " appearances of " + chLoop + " in string " + str);

}

} //main